In an ap the sum of first ten terms is - 150
WebThe sum of n terms of an AP can be easily found out using a simple formula which says that, if we have an AP whose first term is a and the common difference is d, then the formula of the sum of n terms of the AP is S n = … WebMay 14, 2024 · Given: Sum of first ten terms that is, S 10 = -150 and Sum of next ten terms is -550. To find: The A.P. Solution: Let, first term = a Last term = a n We know in an A.P, a n = a + (n – 1) d. For n = 10. a n = a + (10 - 1)d. a n = a + 9d. We know, sum of n terms. s n = \(\frac{n}{2}[a + l]\). l and a n means the last term.. Put the value of l in (1),So, S 10 = …
In an ap the sum of first ten terms is - 150
Did you know?
WebThe third term of an AP is four times the sixth term and the sum of the first ten terms is 150. Find a) The first term and the common difference b) The least number of terms of the Arithmetic Progression which must be taken for the sum to be negative Expert Solution Want to see the full answer? Check out a sample Q&A here See Solution star_border WebJun 24, 2024 · In an A.P., the sum of first ten terms is −150 and the sum of its next ten terms is −550. Find the A.P. Advertisement Expert-Verified Answer 44 people found it …
WebLe a1, a2, ..., a10 are terms of an A.P given S10 = a1+a2+...+10 = 150 But we know that: s10 = (a1+a10)*10/2 = 150 ==> a1+a10 = 150/5 ==> a1+a10 = 30 ==> a10 = 30 - a1...... (1) But a10... WebQuestion 15,10,5,……… In this A.P., sum of first 10 terms is Easy Solution Verified by Toppr 15,10,5,...…. a=15 d=10−15=−5 S n= 2n[2a+(n−1)d] S 10= 210[2×15+(10−1)(−5)] =5[30−5×9] =5[30−45] =5(−15)=−75. Was this answer helpful? 0 0 Similar questions For an arithmetic progression: 5, 211,6, 213,… then T 40−T 20=? Medium View solution >
WebHere, we are given S 10 = - 150 and sum of the next ten terms is - 550. Let us take the first term of the A.P. as a and the common difference as d. So, let us first find a 10. First term = a. Last term = a 10. As, a n = a + ( n - 1) d. For the 10 th term, a 10 = a + ( 10 - 1) d. = a + 9 d. So, here we can find the sum of the n terms of the ... WebIn an AP, the sum of first ten terms is −150 and the sum of its next ten terms is −550. Find the AP. Medium Solution Verified by Toppr S 10=−150 S n= 2n[2a+(n−1)d] S 10= …
WebOct 20, 2024 · Let a be the first term and d be the common difference of the given AP . S₁₀ = -150. ⇒ Sn = n/2 [ 2a + (n-1)d] ⇒ S₁₀ = 10/2 [ 2a + ( 10 - 1 ) d ]. ⇒ -150= 10/2 [ 2a + 9d ] ⇒ …
WebMar 19, 2024 · Given that sum of the first 10 terms of an A.P. is -150. S10 = -150. And the sum of next 10 terms is -550. So, the sum of first 20 terms = Sum of first 10 terms + sum … can minor apply for pancan minor be a member of the companyWebSum In an A.P., the sum of first ten terms is −150 and the sum of its next ten terms is −550. Find the A.P. Advertisement Remove all ads Solution Here, we are given S 10 = -150 and sum of the next ten terms is −550. Let us take the first term of the A.P. as a and the common difference as d. So, let us first find a10. fixer ipswichWebClick here👆to get an answer to your question ️ In an A.P. the sum of first ten terms is \( - 150 \) and the sum of its next ten terms is - Find the A.P CBSE 2010 Sum of the first 14 terms of an A.P. is 1505 and its first term is \( 10 . \) Find its \( 25 ^ { \text { th } } \) term fixer itch.ioWebAnswer to 11. Use the sum of the first ten terms to approximate can minor employees clean bathrooms in alaskaWebSolution for Use the sum of the first ten terms to approximate the sum of the series substitution. Round your answers to three decimal places.) X 4.250 error… fixer ipo 初値予想WebMar 23, 2024 · Since we know that the sum of the first n terms of an A.P. is S n = n 2 [ 2 a + ( n − 1) d] where ‘a’ is the first term and ‘d’ is common difference. We have n=10 and S n = − 150 . ⇒ − 150 = 10 2 [ 2 a + ( 10 − 1) d] ⇒ − 150 = 5 [ 2 a + 9 d] ⇒ − 150 5 = 2 a + 9 d ⇒ − 30 = 2 a + 9 d..... ( 1) Now the sum of the next ten terms is -550. can minor children be beneficiaries